Speaker loads , pls help.

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King_Julian_S

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:walled:

Ok , pls help.

So assuming my amp is 8 ohms.
I really want to connect a set of 8 ohms and 15 ohms together.
The amp is a push pull valve amp so apparently valves does not make a diff in terms of wattage/power.

So my understanding is as follows...
if you connect a 15 + 8 ohm in parallel that you will have a 5.2 ohm load.
Is that correct ?
(15x8) / (15 + 8) .

So will this necessarily be bad ?


Here is another interesting topic I found.
Could I do this ?

"""""
TECH TIP -- If you can 'stand' wasting a little power, here's how to use 8-ohm and 16-ohm speakers together:

a) place an 8-ohm/high-wattage "power dropping" resistor in series with the 8-ohm speaker...thus making it "look" like a 16-ohm load.

b) connect the 16-ohm speaker in parallel with the series-connected 8-ohm speaker-plus-8-ohm dropping resistor...thus making a total combination load of 8-ohms.

c) the volume from both speakers should be approximately equal!

try a weber silencer load. works very well for me

11-03-2006, 08:23 AM
TECH TIP -- If you can 'stand' wasting a little power, here's how to use 8-ohm and 16-ohm speakers together:


Wouldn't this effect the impedance the tubes will see a cross the freq range?
Meaning a single 16ohm speaker vs. 8ohm speaker + 8ohm resistor.

Well I need a trick like that but the other way around, turning a 16ohm speaker to an 8ohm:)
Will a parallel resistor do the trick

""""
 

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